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Double.MaxValue Field

Definition

Represents the largest possible value of a Double. This field is constant.

public const double MaxValue = 1.7976931348623157E+308;

Field Value

Value = 1.7976931348623157E+308

Examples

The following code example illustrates the use of Double.MaxValue:

public class Temperature {
    public static double MinValue {
        get {
            return Double.MinValue;
        }
    }

    public static double MaxValue {
        get {
            return Double.MaxValue;
        }
    }

    // The value holder
    protected double m_value;

    public double Value {
        get {
            return m_value;
        }
        set {
            m_value = value;
        }
    }

    public double Celsius {
        get {
            return (m_value-32.0)/1.8;
        }
        set {
            m_value = 1.8*value+32.0;
        }
    }
}

Remarks

The value of this constant is positive 1.7976931348623157E+308.

The result of an operation that exceeds Double.MaxValue is Double.PositiveInfinity. In the following example, Double.PositiveInfinity results from addition, multiplication, and exponentiation operations when the result exceeds Double.MaxValue.

using System;

public class Example
{
   public static void Main()
   {
      double result1 = 7.997e307 + 9.985e307;
      Console.WriteLine("{0} (Positive Infinity: {1})",
                        result1, Double.IsPositiveInfinity(result1));

      double result2 = 1.5935e250 * 7.948e110;
      Console.WriteLine("{0} (Positive Infinity: {1})",
                        result2, Double.IsPositiveInfinity(result2));

      double result3 = Math.Pow(1.256e100, 1.34e20);
      Console.WriteLine("{0} (Positive Infinity: {1})",
                        result3, Double.IsPositiveInfinity(result3));
   }
}
// The example displays the following output:
//    Infinity (Positive Infinity: True)
//    Infinity (Positive Infinity: True)
//    Infinity (Positive Infinity: True)

Applies to